初学者SQL题目:具有多个COUNT(*)功效的算术
发布时间:2021-05-16 13:13:57 所属栏目:编程 来源:网络整理
导读:继承行使Stack Exchange Data Explorer进修SQL的精力(拜见: Can we become our own “Northwind” for teaching SQL / databases?),我抉择实行编写一个查询来答复一个简朴的题目(关于元): What % of stackoverflow users have over 10,000 rep?. 这就是我所
继承行使Stack Exchange Data Explorer进修SQL的精力(拜见: Can we become our own “Northwind” for teaching SQL / databases?),我抉择实行编写一个查询来答复一个简朴的题目(关于元): What % of stackoverflow users have over 10,000 rep?. 这就是我所做的: Query#1 SELECT COUNT(*) FROM Users WHERE Users.Reputation >= 10000 功效: 556 Query#2 SELECT COUNT(*) FROM USERS 功效: 227691 此刻,我怎样将它们组合成一个查询?这个查询成语叫什么?我必要写什么,以是我可以获得一个像这样的一行三列功效: 556 227691 0,00244190592 办理要领您可以行使 Common Table Expression (CTE):WITH c1 AS ( SELECT COUNT(*) AS cnt FROM Users WHERE Users.Reputation >= 10000 ),c2 AS ( SELECT COUNT(*) AS cnt FROM Users ) SELECT c1.cnt,c2.cnt,CAST(c1.cnt AS FLOAT) / c2.cnt FROM c1,c2 (编辑:湖南网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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