SQL：行使IN子句将字符串转换为IDS

DECLARE @STR_IDS VARCHAR(15)
SET @STR_IDS='7,15,18'
UPDATE TBL_USERS WHERE ID IN  @STR_IDS

我知道更新语句不起浸染,由于ID是INT范例,我正在替代哪里的varachar值.怎样变动查询,以便它将像这样执行？

UPDATE TBL_USERS WHERE ID IN (7,18)

感谢你的保举

办理要领

“Arrays and Lists in SQL Server 2005 and Beyond,When Table Value Parameters Do Not Cut it” by Erland Sommarskog

您必要建设拆分成果.这是支解函数的行使方法：

SELECT
    *
    FROM YourTable                               y
    INNER JOIN dbo.yourSplitFunction(@Parameter) s ON y.ID=s.Value

I prefer the number table approach to split a string in TSQL可是有许多要领可以在SQL Server中拆分字符串,请参阅前面的链接,它表明白每个链接的PRO和CON.

要使Numbers Table要领起浸染,您必要执行一次性表配置,这将建设一个包括1到10,000行的表号：

SELECT TOP 10000 IDENTITY(int,1,1) AS Number
    INTO Numbers
    FROM sys.objects s1
    CROSS JOIN sys.objects s2
ALTER TABLE Numbers ADD CONSTRAINT PK_Numbers PRIMARY KEY CLUSTERED (Number)

配置Numbers表后,建设此拆分成果：

CREATE FUNCTION [dbo].[FN_ListToTable]
(
     @SplitOn  char(1)      --REQUIRED,the character to split the @List string on,@List     varchar(8000)--REQUIRED,the list to split apart
)
RETURNS TABLE
AS
RETURN 
(

    ----------------
    --SINGLE QUERY-- --this will not return empty rows
    ----------------
    SELECT
        ListValue
        FROM (SELECT
                  LTRIM(RTRIM(SUBSTRING(List2,number+1,CHARINDEX(@SplitOn,List2,number+1)-number - 1))) AS ListValue
                  FROM (
                           SELECT @SplitOn + @List + @SplitOn AS List2
                       ) AS dt
                      INNER JOIN Numbers n ON n.Number < LEN(dt.List2)
                  WHERE SUBSTRING(List2,number,1) = @SplitOn
             ) dt2
        WHERE ListValue IS NOT NULL AND ListValue!=''

);
GO

您此刻可以轻松地将CSV字符串拆分为表格并插手个中,可能按照必要行使它,纵然是在动态sql中也是云云.以下是如安在您的题目中行使它：

UPDATE t
    SET Col1=...
    FROM dbo.FN_ListToTable(',','7,18') dt
        INNER JOIN TBL_USERS                t ON  CAST(dt.value AS INT)=t.id

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