如何从SQL Server中的分组值返回动态列(存储过程)
发布时间:2021-01-18 13:05:58 所属栏目:编程 来源:网络整理
导读:我有两个很是相似的环境,我必要天生SP. 在第一种环境下,我必要一个SQL可以或许按勾当数目返回列(假如也许,动态).我必需通过ActivityId建设列. 环境1: Grouping by Date,count(ActivityId) Returning columns: Activity1,Activity2,Activity3 表格1 ╔═════
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我有两个很是相似的环境,我必要天生SP. 在第一种环境下,我必要一个SQL可以或许按勾当数目返回列(假如也许,动态).我必需通过ActivityId建设列. 环境1:
表格1 ╔════════════╦══════════════╗ ║ ActivityId ║ ActivityName ║ ╠════════════╬══════════════╣ ║ 1 ║ Activity 1 ║ ║ 2 ║ Activity 2 ║ ║ 3 ║ Activity 3 ║ ╚════════════╩══════════════╝ 表2 ╔═══════════╦════════════╗ ║ Date ║ ActivityId ║ ╠═══════════╬════════════╣ ║ 1/05/2015 ║ 1 ║ ║ 1/05/2015 ║ 1 ║ ║ 2/05/2015 ║ 2 ║ ║ 3/05/2015 ║ 3 ║ ╚═══════════╩════════════╝ 查询功效 ╔═══════════╦═══════════╦═══════════╦═══════════╗ ║ Date ║ Activity1 ║ Activity2 ║ Activity3 ║ ╠═══════════╬═══════════╬═══════════╬═══════════╣ ║ 1/05/2015 ║ 2 ║ 0 ║ 0 ║ ║ 2/05/2015 ║ 0 ║ 1 ║ 0 ║ ║ 3/05/2015 ║ 0 ║ 0 ║ 1 ║ ╚═══════════╩═══════════╩═══════════╩═══════════╝ 案例2:
表格1 ╔════════════╦═══════════╦═══════╗ ║ Date ║ Account ║ Value ║ ╠════════════╬═══════════╬═══════╣ ║ 30/05/2015 ║ 1 ║ 10 ║ ║ 27/05/2015 ║ 2 ║ 40 ║ ╚════════════╩═══════════╩═══════╝ 查询功效: ╔═════════╦════════════╦════════════╦════════════╦════════════╦═════════════════════╗ ║ Account ║ 30/05/2015 ║ 29/05/2015 ║ 28/05/2015 ║ 27/05/2015 ║…each day in a month ║ ╠═════════╬════════════╬════════════╬════════════╬════════════╬═════════════════════╣ ║ 1 ║ 10 ║ 0 ║ 0 ║ 0 ║ ║ ║ 2 ║ 0 ║ 0 ║ 0 ║ 40 ║ ║ ╚═════════╩════════════╩════════════╩════════════╩════════════╩═════════════════════╝ 办理要领对付案例1,试试这个:--Creating Test tables
create table #activity
(
ActivityId TINYINT,ActivityName VARCHAR(20)
)
create table #date
(
[Date] DATE,ActivityId TINYINT
)
INSERT INTO #activity VALUES(1,'Activity 1')
INSERT INTO #activity VALUES(2,'Activity 2')
INSERT INTO #activity VALUES(3,'Activity 3')
INSERT INTO #date VALUES('2015-05-01',1)
INSERT INTO #date VALUES('2015-05-01',1)
INSERT INTO #date VALUES('2015-05-02',2)
INSERT INTO #date VALUES('2015-05-03',3)
DECLARE @activities NVARCHAR(MAX)
DECLARE @stmt NVARCHAR(MAX)
SET @activities = ''
SET @stmt = ''
--Get List of Activities
SELECT @activities = @activities + ',[' + ActivityName + ']'
FROM #activity
SET @activities = RIGHT(@activities,LEN(@activities)-1) --Remove Leading Comma
--Build PIVOT Statement
SET @stmt = 'SELECT [Date],' + @activities + '
FROM (SELECT d.[Date],a.ActivityName
FROM #date d
INNER JOIN #activity a ON d.ActivityId = a.ActivityId) tab
PIVOT (COUNT(ActivityName) FOR ActivityName IN (' + @activities + ')) AS NumberOfActivities'
--Execute
EXEC sp_executesql @stmt
--CleanUp
DROP TABLE #activity
DROP TABLE #date (编辑:湖南网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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