php数据会见例子：租房信息打点，详细内容如下

1.数据库建表

2. zufangzi.php

<div class="jb51code">
<pre class="brush:xhtml;">

租屋子

<form action="zufangzi.php" method="post">

<table width="100%" border="1" cellpadding="0" cellspacing="0">
<tr>
<td>要害字</td>
<td>地区</td>
<td>构筑面积</td>
<td>租金</td>
<td>租赁范例</td>
<td>衡宇范例</td>
</tr>
<?php

$tj1 = " 1=1 ";
$tj2 = " 1=1 ";
$tj3 = " 1=1 ";
$tj4 = " 1=1 ";

if(!empty($_POST["qy"]))
{
$aqy = $_POST["qy"];
$sqy = implode("','",$aqy);

$tj1 = " area in ('{$sqy}') ";

}

if(!empty($_POST["zl"]))
{
$azl = $_POST["zl"];
$szl = implode("',$azl);

$tj2 = " renttype in ('{$szl}') ";

}

if(!empty($_POST["fw"]))
{
$afw = $_POST["fw"];
$sfw = implode("',$afw);

$tj3 = " housetype in ('{$sfw}') ";

}

if(!empty($_POST["key"]))
{
$k = $_POST["key"];
$tj4 = " keyword like '%{$k}%' ";
}

$sql = "select * from house where {$tj1} and {$tj2} and {$tj3} and {$tj4}";
echo $sql;

$arr = $db->query($sql);
foreach($arr as $v)
{
echo "<tr>
<td>{$v[1]}</td>
<td>{$v[2]}</td>
<td>{$v[3]}</td>
<td>{$v[4]}</td>
<td>{$v[5]}</td>
<td>{$v[6]}</td>
</tr>";
}
?>
</table>

所引用的封装类

$result = $db->query($sql);

if($type)
{
  //假如是查询，表现数据
  return $result->fetch_all();
}
else
{
  //假如是增编削，返回true可能false
  return $result;
}

}
}

泛起页面

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